Nine men went to a restaurant. Eight of them spent $6 each for their meals and the ninth man spent $4 more than the average expenditure of all nine men. What is the average expenditure?
Average simply is the sum of a set of data divided by the quantity of the data.
We know what 8 men spent which is $6 each Let what the ninth man spent be = Y Let the average of what the nine men spent be = Z
the ninth man spent $4 more than the average expenditure of all nine men
So, Y = Z + 4 (eqn 1)
average of what all nine men spent will then be ((6 x 8) + Y) ÷ 9 = Z (48 + Y) ÷ 9 = Z
Multiply all through by 9 48 + Y = 9Z (eqn 2)
Put eqn 1 into eqn 2 48 + Z + 4 = 9Z 52 + Z = 9Z 52 = 9Z - Z 52 = 8Z Z = 52 ÷ 8 Z = 6.5
Nine men went to a restaurant. Eight of them spent $6 each for their meals and the ninth man spent $4 more than the average expenditure of all nine men. What is the average expenditure?
Average simply is the sum of a set of data divided by the quantity of the data.
We know what 8 men spent which is $6 each Let what the ninth man spent be = Y Let the average of what the nine men spent be = Z
the ninth man spent $4 more than the average expenditure of all nine men
So, Y = Z + 4 (eqn 1)
average of what all nine men spent will then be ((6 x 8) + Y) ÷ 9 = Z (48 + Y) ÷ 9 = Z
Multiply all through by 9 48 + Y = 9Z (eqn 2)
Put eqn 1 into eqn 2 48 + Z + 4 = 9Z 52 + Z = 9Z 52 = 9Z - Z 52 = 8Z Z = 52 ÷ 8 Z = 6.5
So, average of the expenditure is $6.5
Answer: $6.5
BY Riddles Repository - Answers
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